Virgin Lake, Wyoming, United States
About
Virgin Lake is a lake located in Fremont county Wyoming in the United States of America. It is at 43.7097124 latitude and -109.6723418 longitude. Virgin Lake is at an elevation of 2800 ft (9186 m). The USGS map that contains this location is titled "Ramshorn Peak".
Location Details
| Type of Place: | Lake |
| Latitude: | 43.7097124 |
| Longitude: | -109.6723418 |
| Elevation: | 2800 ft / 9186 m |
| County: | Fremont |
| USGS Map Name: | Ramshorn Peak |
