Township of Douglas, Iowa, United States
About
Township of Douglas is a civil located in Webster county Iowa in the United States of America. It is at 42.5164382 latitude and -94.2679667 longitude. Township of Douglas is at an elevation of 345 ft (1132 m). The USGS map that contains this location is titled "Clare".
Location Details
| Type of Place: | Civil |
| Latitude: | 42.5164382 |
| Longitude: | -94.2679667 |
| Elevation: | 345 ft / 1132 m |
| County: | Webster |
| USGS Map Name: | Clare |
