Selinsgrove, Pennsylvania, United States
About
Selinsgrove is a populated place located in Snyder county Pennsylvania in the United States of America. It is at 40.7989736 latitude and -76.8621935 longitude. Selinsgrove is at an elevation of 136 ft (446 m). The USGS map that contains this location is titled "Sunbury".
Location Details
| Type of Place: | Populated Place |
| Latitude: | 40.7989736 |
| Longitude: | -76.8621935 |
| Elevation: | 136 ft / 446 m |
| County: | Snyder |
| USGS Map Name: | Sunbury |
