Oxbow Park, Iowa, United States
About
Oxbow Park is a park located in Humboldt county Iowa in the United States of America. It is at 42.7360827 latitude and -94.254131 longitude. Oxbow Park is at an elevation of 332 ft (1089 m). The USGS map that contains this location is titled "Unique".
Location Details
| Type of Place: | Park |
| Latitude: | 42.7360827 |
| Longitude: | -94.254131 |
| Elevation: | 332 ft / 1089 m |
| County: | Humboldt |
| USGS Map Name: | Unique |
