Jefferson, Indiana, United States
About
Jefferson is a populated place located in Clinton county Indiana in the United States of America. It is at 40.2794807 latitude and -86.5900034 longitude. Jefferson is at an elevation of 262 ft (860 m). The USGS map that contains this location is titled "Frankfort".
Location Details
| Type of Place: | Populated Place |
| Latitude: | 40.2794807 |
| Longitude: | -86.5900034 |
| Elevation: | 262 ft / 860 m |
| County: | Clinton |
| USGS Map Name: | Frankfort |
