Elkhorn Hill, Indiana, United States
About
Elkhorn Hill is a summit located in Franklin county Indiana in the United States of America. It is at 39.3544975 latitude and -84.8874552 longitude. Elkhorn Hill is at an elevation of 308 ft (1010 m). The USGS map that contains this location is titled "Cedar Grove".
Location Details
| Type of Place: | Summit |
| Latitude: | 39.3544975 |
| Longitude: | -84.8874552 |
| Elevation: | 308 ft / 1010 m |
| County: | Franklin |
| USGS Map Name: | Cedar Grove |
