Cuba, New York, United States
About
Cuba is a populated place located in Allegany county New York in the United States of America. It is at 42.2175668 latitude and -78.2752927 longitude. Cuba is at an elevation of 456 ft (1496 m). The USGS map that contains this location is titled "Cuba".
Location Details
| Type of Place: | Populated Place |
| Latitude: | 42.2175668 |
| Longitude: | -78.2752927 |
| Elevation: | 456 ft / 1496 m |
| County: | Allegany |
| USGS Map Name: | Cuba |
