Chapin Hill, New York, United States

About

Chapin Hill is a summit located in Sullivan county New York in the United States of America. It is at 41.6014789 latitude and -74.8373864 longitude. Chapin Hill is at an elevation of 435 ft (1427 m). The USGS map that contains this location is titled "Highland Lake".

Location Details

Type of Place:Summit
Latitude:41.6014789
Longitude:-74.8373864
Elevation:435 ft / 1427 m
County:Sullivan
USGS Map Name:Highland Lake

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