Bucktooth Island, New York, United States
About
Bucktooth Island is a island located in Cattaraugus county New York in the United States of America. It is at 42.1592296 latitude and -78.7730887 longitude. Bucktooth Island is at an elevation of 412 ft (1352 m). The USGS map that contains this location is titled "Little Valley".
Location Details
Type of Place: | Island |
Latitude: | 42.1592296 |
Longitude: | -78.7730887 |
Elevation: | 412 ft / 1352 m |
County: | Cattaraugus |
USGS Map Name: | Little Valley |