Borough of Selinsgrove, Pennsylvania, United States
About
Borough of Selinsgrove is a civil located in Snyder county Pennsylvania in the United States of America. It is at 40.8002404 latitude and -76.8646162 longitude. Borough of Selinsgrove is at an elevation of 134 ft (440 m). The USGS map that contains this location is titled "Sunbury".
Location Details
| Type of Place: | Civil |
| Latitude: | 40.8002404 |
| Longitude: | -76.8646162 |
| Elevation: | 134 ft / 440 m |
| County: | Snyder |
| USGS Map Name: | Sunbury |
