Ashbaugh Hill, New York, United States
About
Ashbaugh Hill is a summit located in Steuben county New York in the United States of America. It is at 42.2831261 latitude and -77.6433238 longitude. Ashbaugh Hill is at an elevation of 504 ft (1654 m). The USGS map that contains this location is titled "Hornell".
Location Details
| Type of Place: | Summit |
| Latitude: | 42.2831261 |
| Longitude: | -77.6433238 |
| Elevation: | 504 ft / 1654 m |
| County: | Steuben |
| USGS Map Name: | Hornell |
