8 Acre Park, Florida, United States
About
8 Acre Park is a park located in Polk county Florida in the United States of America. It is at 28.1241667 latitude and -81.6244444 longitude. 8 Acre Park is at an elevation of 52 ft (171 m). The USGS map that contains this location is titled "Dundee".
Location Details
| Type of Place: | Park |
| Latitude: | 28.1241667 |
| Longitude: | -81.6244444 |
| Elevation: | 52 ft / 171 m |
| County: | Polk |
| USGS Map Name: | Dundee |
